Two particles each have a mass of 6.0 times l0-3 kg, but carry opposite charges

Question

Two particles each have a mass of 6.0 times l0-3 kg, but carry opposite charges of + 5.0 times 10-6 C and -5.0 times 10-6 respectively and are initially held at a distance of 0.80 m apart. Both are then released and accelerate toward each other. How fast is each particle moving when the separation between them is one-third its initial value?

Explanation / Answer

Initial K.E. + Initial P.E. = Final K.E. + Final P.E. =>0 + (9*(10^9)*5*(10^(-6))*(-5)*(10^(-6)))/(0.8) = 6*(10^(-3))*v^2 + (9*(10^9)*5*(10^(-6))*(-5)*(10^(-6)))/(0.8/3) =>6*(10^(-3))*v^2 = 0.5625 =>v = 9.6825 m/s

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