A 4.20 kg block is pushed along a floor by a constant applied force that is hori

Question

A 4.20 kg block is pushed along a floor by a constant applied force that is horizontal and has a magnitude of 40.0 N. Figure 6-27 gives the block's speed v versus time t as the block moves along an x axis on the floor. The scale of the figure's vertical axis is set by vs = 5.00 m/s. What is the coefficient of kinetic friction between the block and the floor?

Explanation / Answer

t = 0 => u = 0.5 m/s t = 0.1 => v = 1 m/s v = u+at =>0.5 = a*0.1 =>a = 5 m/s^2 Vertical direction: N = 4.2*9.81 N Horizontal direction: 40 = (4.2*5)+(u*N) =>u = 0.46114 = the coefficient of kinetic friction between the block and the floor

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