(a) What is the tangential acceleration of a bug on the rim of a 9.0 in. diamete

Question

(a) What is the tangential acceleration of a bug on the rim of a 9.0 in. diameter disk if the disk moves from rest to an angular speed of 79 rev/min in 5.0 s? Incorrect: .3830 Your answer is incorrect. Your response differs from the correct answer by more than 100%. m/s2 (b) When the disk is at its final speed, what is the tangential velocity of the bug? Incorrect: 0 Your answer is incorrect. The correct answer is not zero. m/s (c) One second after the bug starts from rest, what is its tangential acceleration? What is its centripetal acceleration? What is its total acceleration? Correct: 57.2 Your answer is correct.

Explanation / Answer

? = 80rev/min * 2p rad/rev * 1min/60s = 8.38 rad/s a = ?? / ?t = 8.38rad/s / 3s = 2.79 rad/s² 5in * 2.54cm/in = 12.7 cm = 0.127 m a) a = a r = 2.79rad/s² * 0.127m = 0.35 m/s² b) v = ?r = 8.38rad/s * 0.127m = 1.06 m/s c) Still 0.35 m/s², I believe. I assume that the next two also pertain to "one second after the bug starts from rest." ? = a t = 2.79rad/s² * 1s = 2.79 rad/s d) a = ?²r = (2.79 rad/s)² * 0.127m = 0.99 m/s² e) a_tot = v(0.35² + 0.99²) m/s² = 1.05 m/s² T = arctan(1.05/0.35) = 71º

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