(a) What is the tangential acceleration of a bug on the rim of a10.0 in. diamete

Question

(a) What is the tangential acceleration of a bug on the rim of a10.0 in. diameter disk if the diskmoves from rest to an angular speed of 76 rev/min in 3.0s?
1 m/s2

(b) When the disk is at its final speed, what is the tangentialvelocity of the bug?
2 m/s

(c) One second after the bug starts from rest, what is itstangential acceleration?
3 m/s2
What is its centripetal acceleration?
4 m/s2
What is its total acceleration?
5 m/s2
6°(relative to the tangentialacceleration)

How do you find degrees relative to tangential acceleration? Ican't seem to get the correct answer.

Explanation / Answer

we have       = tan-1 (ar / at ) Where        ar = 0.89 m/s2        at = 0.95 m/s2 Therefore          =tan-1 ( 0.89 / 0.95)            = 43.13o

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