(a) What is the tangential acceleration of a bug on the rim of a10.0 in. diamete

Question

(a) What is the tangential acceleration of a bug on the rim of a10.0 in. diameter disk if the diskmoves from rest to an angular speed of 76 rev/min in 3.0s?
1 m/s2

(b) When the disk is at its final speed, what is the tangentialvelocity of the bug?
2 m/s

(c) One second after the bug starts from rest, what is itstangential acceleration?
3 m/s2
What is its centripetal acceleration?
4 m/s2
What is its total acceleration?
5 m/s2
6°(relative to the tangentialacceleration)

How do you find relative to tangential acceleration? Ican't seem to get the correct answer.

Explanation / Answer

You need both the tangential and centripetal acceleration to getthis one. The tangential acc. is 0.34 at zero degrees, in thedirection of motion, and the centripetal acc. is 0.89 at 90degrees, because the centripetal acceleration is always pointing tothe center of the circle, at a right angle to the direction ofmotion. (I'm trusting that you got the right numbers forthose.) So, use inverse tangent to find the angle that these two vectorsmeet: = tan-1(y / x) = tan-1(0.89 / 0.34) = tan-1(2.61) = 69 degrees

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