In an amusement park ride called the Rotor, a circular, 4.0 m radius room is spu

Question

In an amusement park ride called the Rotor, a circular, 4.0 m radius room is spun around at high speed and then the floor is removed. The people riding the Rotor feel that they are being pressed against the wall with such a large force that they do not slide down the wall to the floor. The coefficient of friction between the riders and the wall is (0.6,0.5). Find everything you can about this problem.

*Please SHOW me how to do this and what equations ur using without skipping steps. Show a step-by step fashion!

Explanation / Answer

normal force due to wall = centrepetal force = mv^2/R let room be spinning with velocity v so vertical force opposing gravity = uN = u(m*v^2)/4 so mg = u(m*v^2)/4 so g = u(v^2)/4 given u = (0.6,0.5) when u = 0.6 v = 8.08 m/s when u = 0.5 v = 8.85 m/s so for the people to be safe, the speed shud be greater than 8.08m/s

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