The six situations in the figure show pairs of cars, all of which are identical.
ID: 2213813 • Letter: T
Question
The six situations in the figure show pairs of cars, all of which are identical. The velocity of each car is given in the figure. In each case, CAR #1 honks its horn. Rank the situations from highest to lowest based on the frequency heard by CAR #2. Ties are possible. Use the symbols > and = to indicate your ranking, listing any that are equal in alphabetical order.For example, if Y and Z are the same and are both greater than X, then you would enter Y=Z>X (note: Z=Y>X would be incorrect, since Y and Z, being equal, must be in alphabetical order). FROM HIGHEST TO LOWEST FREQUENCY.
In which cases does the doppler effect not apply?
The six situations in the figure show pairs of cars, all of which are identical. The velocity of each car is given in the figure. In each case, CAR #1 honks its horn. Rank the situations from highest to lowest based on the frequency heard by CAR #2. Ties are possible. Use the symbols > and = to indicate your ranking, listing any that are equal in alphabetical order.For example, if Y and Z are the same and are both greater than X, then you would enter Y=Z>X (note: Z=Y>X would be incorrect, since Y and Z, being equal, must be in alphabetical order). FROM HIGHEST TO LOWEST FREQUENCY. In which cases does the doppler effect not apply?Explanation / Answer
fo = (v+u0)/(v-us) x fs, u0- speed of car2, us - speed of car1 f0- frequency heard by car2, fs - frequency from car1 a) u0 -ve,us +ve f0= (340-40)/(340-20) x v0 = 0.939v0 d)u0 -ve,us +ve f0= (340-20)/(340-40) x v0 =1.06v0 b)u0 +ve,us +ve f0= (340+20)/(340-20) x v0 = 1.125v0 e)u0 -ve,us +ve f0= (340-20)/(340-20) x v0 = v0 c)u0 -ve,us -ve f0= (340-20)/(340+20) x v0 = 0.88v0 F)u0 +ve,us +ve f0= (340+40)/(340-20) x v0 = 1.18v0 so B>F>D>E>A>C
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