Forces in a Three-Charge System Coulomb\'s law for the magnitude of the force be

Question

Forces in a Three-Charge System Coulomb's law for the magnitude of the force between two particles with charges and separated by a distance is , where , and is the permittivity of free space. Consider two point charges located on the x axis: one charge, = -16.0 , is located at = -1.710 ; the second charge, = 32.0 , is at the origin . Part A What is the net force exerted by these two charges on a third charge = 55.0 placed between and at = -1.140 ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures.

Explanation / Answer

Since Q1 is negative and to the left of Q3 the force will be to the left Since Q2 is positive and to the right of Q3 the the force will also be to the left Therefore you can add the forces together (with left being negative) Now we have F = -k*Q1*Q3/r13^2 - k*Q2*Q3/r23^2 = -9.0x10^9*12x10^-9*55x10^-9/(1.705 - 1.155)^2 - 9.0x10^9*36.5x10^-9*55x10^-9/1.155^2 = -3.32x10^-5N please rate me...

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