A block of ice of mass 4.30kg is placed against a horizontal spring that has for

Question

A block of ice of mass 4.30kg is placed against a horizontal spring that has force constant k = 170N/m and is compressed a distance 2.40 times 10-2 m. The spring is released and accelerates the block along a horizontal surface. You can ignore friction and the mass of the spring. Calculate the work done on the block by the spring during the motion of the block from its initial position to where the spring has returned to its uncompressed length. Express your answer using two significant figures. What is the speed of the block after it leaves the spring? Express your answer using two significant figures.

Explanation / Answer

W = 1/2kx^2 W = 0.5*170*(0.024m)^2 = 0.04896 J PE = 0.04896 J, but PE = KE so 0.04896 J = 0.5mv^2 = 0.5(4.3kg)*v^2 v = 0.15m/s Hope this helps! Please comment before giving a low rating, ratings are permanent, thanks!

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