Two long, parallel wires carry currents of I1 = 2.84 A and I2 = 4.95 A in the di

Question

Two long, parallel wires carry currents of I1 = 2.84 A and I2 = 4.95 A in the direction indicated in the figure below. (Choose the line running from wire 1 to wire 2 as the positive x-direction and the line running upward as the positive y-direction.) Find the magnitude and direction of the magnetic field at a point midway between the wires (d = 20.0 cm), magnitude mu T direction degree (counterclockwise from the +x-axis) Find the magnitude and direction of the magnetic field at point P, located d = 20.0 cm above the wire carrying the 4.95-A current, magnitude mu T direction degree (counterclockwise from the +x-axis)

Explanation / Answer

B= ui/(2*pi*r) a) Magnitude = 4.22*10^-6 T (direction: Y+ ) b) B = (7.79*10^-6 (-i) + 2.84*10^-6 (-j))T.. therefore magnitude = 8.2915 *10^-6 T (direction: 159.96 degree from X+ in counterclockwise direction)

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