Chegg cannot allow me to add more points right now, i promise to add more points
ID: 2241461 • Letter: C
Question
Chegg cannot allow me to add more points right now, i promise to add more points as soon as the question is coreect and chegg allows me to add more points.
Explanation / Answer
6. First find the number of moles, n:
PV = nRT ==> n = PV / RT
22 C + 273 C = 295 K
n = (10 Pa / 101325 Pa) (0.25 m^3)(1000) / (0.082 L-atm/ mol K) (295 K)
n = (9.87 x 10^-5) (250) / 24)
n = 1.028 x 10^-3 mol
Now, get molecules of gas: (1.028 x 10^-3 mol) ( 6.022 x 10^23) = 6.19 x 10^20 molecules of gas [ANS]
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7. This one is pretty easy if you know this equation:
W = nRT ln (V2/ V1)
W = (6.10 mol) (8.3144 J/mol.K) (280 K) ln (3.75 L / 1.33 L)
W = Q (since this is an isothermal process)
Q = 1.47 x 10^4 J [ANS]
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8. Again, the equation for Work is handy, and we can find final and initial volume from the graph (V2 and V1, respectively). However, we need to find the temperature. The cool thing is, during isothermal process, temperature is constant, so T1 and T2 (initial and final temperature doesn
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