In the hydraulic system shown in the figure below the piston on the left has a d

Question

In the hydraulic system shown in the figure below the piston on the left has a diameter of 4.7 cm and a mass of 1.8 kg. The piston on the right has a diameter of 12 cm and a mass of 2.5 kg. If the density of the fluid is 750 kg/m3, what is the height difference h between the two pistons?

In the hydraulic system shown in the figure below the piston on the left has a diameter of 4.7 cm and a mass of 1.8 kg. The piston on the right has a diameter of 12 cm and a mass of 2.5 kg. If the density of the fluid is 750 kg/m3, what is the height difference h between the two pistons?

Explanation / Answer

Pl=Pr

M1g /A1 = mr g /Ar +pgh

H= 4 /pie(750) [1.8/ (0.047)^2 -2.5 / (0.12)^2   ]

0.00169 x641.23723655=1.08369092977 = 1.08 m answer

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