A classroom demonstration is done with an Atwood machine. The masses are m 1 = 1

Question

A classroom demonstration is done with an Atwood machine. The masses are m1 = 1.0 kg and m2 = 1.18 kg. If the larger mass descends a distance of 2.9 m from rest in 2.6732 s, what is the acceleration of gravity at that place? (Ignore the effects of pulley mass and friction.)

A classroom demonstration is done with an Atwood machine. The masses are m1 = 1.0 kg and m2 = 1.18 kg. If the larger mass descends a distance of 2.9 m from rest in 2.6732 s, what is the acceleration of gravity at that place? (Ignore the effects of pulley mass and friction.)

Explanation / Answer

m2g-T= m2a

T- m1g=m1a

a=(m2-m1)g/(m1+m2)

= (0.18/2.18)g

=0.08257g

now,

s= 0.5 a t^2

a= 2.9/(0.5*2.6732^2)

=0.81164

g= 0.81164/0.08257

=9.8297 m/s^2

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