Four square sheets of thin metal are joined into a single object as shown. Each
ID: 2261623 • Letter: F
Question
Four square sheets of thin metal are joined into a single object as shown. Each of the four original squares has mass 200 g, and has sides of length 22 cm. The inset picture shows the moment of inertia of a single square sheet about its center of mass. What is the moment of inertia about an axis located at point 1?
Explanation / Answer
moment of inertia of a plank abot an axis passing through its center.
I = M*L^2/6
moment of inerta of block1 about the point 1 is
I1 = M*L^2/6 + M*d^2 (according to parallel axis theorem)
here d = sqrt(2)*L/2
= M*L^2/6 + M*L^2/2
= (4/6)*M*L^2
= (2/3)*M*L^2
in the simillar way
for block2, I2 = (2/3)*M*L^2
for block3, I3 = (2/3)*M*L^2
for block4, I4 = M*L^2/3 + M*d^2 (according to parallel axis theorem)
here d = sqrt( L^2/4 + 9*L^2/4)
= sqrt(10)*L/2
I4 = M*L^2/6 + M*10*L^2/4
= (2*M*L^2 + 30*M*L^2)/12
= (32/12)*M*L^2
I = I1+I2+I3 + I4
= 3*(2/3)*M*L^2 + (32/12)*M*L^2
= (24*M*L^2 + 32*M*L^2)/12
= (56/12)*M*L^2
I = (56/12)*0.2*0.22^2
= 0.04517 kg.m^2
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.