A uniform meter stick of mass M has an empty paint can of mass m hanging from on

Question

A uniform meter stick of mass M has an empty paint can of mass m hanging from one end. The meter stick and the can balance at a point 25.5 cm from the end of the stick where the can is attached. When the balanced stick-can system is suspended from a scale, the reading on the scale is 2.29 N. Find the mass of the following. (a) the meter stick
kg

(b) the paint can
kg A uniform meter stick of mass M has an empty paint can of mass m hanging from one end. The meter stick and the can balance at a point 25.5 cm from the end of the stick where the can is attached. When the balanced stick-can system is suspended from a scale, the reading on the scale is 2.29 N. Find the mass of the following. (a) the meter stick
kg

(b) the paint can
kg A uniform meter stick of mass M has an empty paint can of mass m hanging from one end. The meter stick and the can balance at a point 25.5 cm from the end of the stick where the can is attached. When the balanced stick-can system is suspended from a scale, the reading on the scale is 2.29 N. Find the mass of the following. (a) the meter stick
kg

(b) the paint can
kg (a) the meter stick
kg

(b) the paint can
kg

Explanation / Answer

The total mass of stick + can = 2.29 N

Let the mass os stick be M ...
so mass of can = 2.29 / 9.8 - M

taking moment of all the forces about the pivot..

(50-25.5)*M*9.8 = 25.5 * ( 2.29 - 9.8 M )
19.215687 M = 2.29

so M = 0.11917 kg ...

a) mass of meter scale = 0.15683 kg ..

b) mass of can = (2.29/9.8) - 0.11917 = 0.11450347 kg

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