The figure above shows two charges, q1 = +2Q and q2 = -Q. The surface S3 enclose

Question

The figure above shows two charges, q1 = +2Q and q2 = -Q. The surface S3 encloses both charges, SI encloses q1, S2 encloses q2 and S4 does not enclose any of the two charges. (Note: e0 stands for epsilon.0.) The electric flux enclosed by S2 is . The electric flux enclosed by S4 is . The total electric flux enclosed by SI and S2 is The electric flux enclosed by S1 is The electric flux enclosed by S3 is The contents of this web site are for use by the students enrolled in this course only. Any distribution of the contents in whole or in parts and in any form, including posting on the web or in printed version, is a violation of the Copyright laws and the FSU honor codes.

Explanation / Answer

According to gauss law flux of electric field = Q/(epsilon ) where Q is the charge enclosed.

as in S2 charge enclosed is q2 = -Q flux = -Q/(epsilon)

flux in S4 is 0 as there is no charge enclosed

flux in S1 = q1/epsilon = 2Q/epsilon

flux in S1 + flux in S2 = 2Q/epsilon + -Q/epsilon = Q/epsilon

Flux enclosed by S3 = net charge/epsilon = Q/epsilon

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