In the previous problem, you can get an approximate answer for the electric fiel

Question

In the previous problem, you can get an approximate answer for the electric field at point P by using the electric dipole approximation which is valid for the limit x>>d. Calculate the magnitude of the electric field at point P with this approximation and the same values for Q, d and x as in the previous problem.

Two charges, +q and -q, are located in the x-y plane at points (0,+d/2) and (0,-d/2), respectively. Calculate the magnitude of the electric field at point P with the superposition principle. Data: q = 24.0 nC, d = 4.20 mm and P is at x = 84.0 mm. In the previous problem, you can get an approximate answer for the electric field at point P by using the electric dipole approximation which is valid for the limit x>>d. Calculate the magnitude of the electric field at point P with this approximation and the same values for Q, d and x as in the previous problem.

Explanation / Answer

distance from charge to the point P,

r = sqrt(2.1^2+84^2 = 84.03 mm = 0.08403 m

theta = tan^-1(2.1/84) = 1.432 degrees

E1 = E2 = k*q/r^2 = 9*10^9*24*10^-9/0.08403^2 = 30590 N/c

here, angle between E1 and E2, = 180-2*1.432 = 177.136


Enet = sqrt(E1^2+E2^2 + 2*E1*E2*cos(177.136)) = 1529 N/c

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