In the previous problem, you can get an approximate answer for the electric fiel

Question

In the previous problem, you can get an approximate answer for the electric field at point P by using the electric dipole approximation which is valid for the limit x>>d. Calculate the magnitude of the electric field at point P with this approximation and the same values for Q, d and x as in the previous problem.

Two charges, +q and -q, are located in the x-y plane at points (0,+d/2) and (0,-d/2), respectively. Calculate the magnitude of the electric field at point P with the superposition principle. Data: q = 24.0 nC, d = 4.20 mm and P is at x = 84.0 mm. In the previous problem, you can get an approximate answer for the electric field at point P by using the electric dipole approximation which is valid for the limit x>>d. Calculate the magnitude of the electric field at point P with this approximation and the same values for Q, d and x as in the previous problem.

Explanation / Answer

a) E(+q) = k*q/r^2 = 9.0x10^9*24.0x10^-9/(0.084- 0.00420/2)^2 = 3.39x10^4N/C (+x)

Now E(-q) = k*q/r^2 = 9.0x10^9*24.0x10^-9/(0.084 + 0.00420/2)^2 = 2.776x10^4N/C (-x)

So E net = 8.75x10^4N/C - 7.92x10^4N/C = 6152.79N/C (+x)


b) The approximation for E = 2*k*q*d/x^3 = 2*9.0x10^9*24.0x10^-9*2.8x10^-3/(0.056^3... = 6887.75N/C

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.