Two charged balls are placed at different locations on the x-axis. Ball 1 is at

Question

Two charged balls are placed at different locations on the x-axis. Ball 1 is at x = -2.00 m, while ball 2 is at x = +1.00 m. One of the graphs above shows the electric potential, due to these two balls, as a function of position on the x-axis. The other graph shows the net electric field, due to these two balls, as a function of position on the x-axis, with positive meaning the field is directed right, and negative meaning that the field is directed left. Note that one of the graphs passes through zero at x = 0.

(a) Select all the correct statements about this situation from the list below.

-The orange graph represents the electric potential, while the green graph represents the electric field.

-The green graph represents the electric potential, while the orange graph represents the electric field.

-Both the electric potential and the electric field are zero at x = 0.

-Ball 1 has a positive charge.

-Ball 1 has a negative charge.

-Ball 2 has a positive charge.

-Ball 2 has a negative charge.

-We can't say for sure what the signs on the charges are, but we can say that they are either both positive or both negative.

-We can't say for sure what the signs on the charges are, but we can say that one is positive and the other is negative.

(b) If one of the balls has a charge of +20.0 nanocoulombs, what is the charge on the other ball?

Explanation / Answer

The orange graph represent the electric potential while the green graph represent electric field. True

We cannot say for sure what the signs on the charges are, but we can say that they are either both positive or both negative. True

b) As we know that

E=E1 + (- E2)=0

K q1/ r12 = k q2 / r22

   q1=q2 r12 / r22

q1= (20 * 10-9) 12/ 22

     q1=5* 10-9 C

( q1= 5nC) answer

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