An electron is released from rest at a negative plate of parallel-plate capacito

Question

An electron is released from rest at a negative plate of parallel-plate capacitor. If the distance across the plate Is 10mm and the potential difference across the plate is 100v, with what velocity does the electron hit the positive plate? (M=9.1x10^-31kg, e= 1.6x10^-19 C) An electron is released from rest at a negative plate of parallel-plate capacitor. If the distance across the plate Is 10mm and the potential difference across the plate is 100v, with what velocity does the electron hit the positive plate? (M=9.1x10^-31kg, e= 1.6x10^-19 C)

Explanation / Answer

1/2mv2=qV

v=sqrt(2qV/m)=sqrt( 2 x 1.6x10-19 x 100/9.11x10-31)

v=sqrt(35.126x1012)=5.9x106m/s

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