An electron is near a positive ion of charge +9e and a negative ion or charge -8

Question

An electron is near a positive ion of charge +9e and a negative ion or charge -8e (see the figure below. (Take a = 4.88 mu m, b = 4.24 mu m, and = 59.5 degree.) Find the magnitude and direction of the resultant force on the electron. (Let right be the +x-direction. Measure the angle counter-clockwise from the +x-axis.) magnitude direction degree Find the magnitude and direction of the electron's instantaneous acceleration (Let right be the +x-direction. Measure the angle counter-clockwise from the +x-axis.) magnitude direction degree

Explanation / Answer

magnitude=9*10^9*9*e*e/a^2=8.7*10^(-17) N similarly, force due to -8e will be repulsive in nature and will be along the line connecting -8e and electron in 4th quadrant. i.e. along the direction of (cos theta i - sin theta j ) magnitude=9*10^9*8*e*e/(3*10^(-6))^2=2.048*10^(-16) N net force=(0.1694 i - 1.845 j )*10^(-16) magnitude=1.8527*10^(-16) N direction=84.75 degree in anticlockwise direction b)acceleration=force/mass= magnitude of acceleration=2.0359*10^14 m/s^2 direction=84.75 degree in anticlockwise

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