An electron is fired through a pair of deflection plates, which produce a 2.00 c

Question

An electron is fired through a pair of deflection plates, which produce a 2.00 cm long region with an electric field of 4000 N/C perpendicular to the electron's initial velocity. If the initial speed of the electron is 1.00e7 m/s, what angle will its new velocity make with the direction of the original velocity?

The answer is 8.0 degrees.  Could you please explain the process?  Thank you!
An electron is fired through a pair of deflection plates, which produce a 2.00 cm long region with an electric field of 4000 N/C perpendicular to the electron's initial velocity. If the initial speed of the electron is 1.00e7 m/s, what angle will its new velocity make with the direction of the original velocity?

The answer is 8.0 degrees.  Could you please explain the process?  Thank you!

Explanation / Answer

Vy=qE*L/(m*vx)=14.05*10^5 m/s....

theta=tan^-1(vy/vx)=7.96 degrees=8 degrees..

here vx=10^7 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.