An electron is near a positive ion of charge \"9e and a negative ion of charge $

Question

An electron is near a positive ion of charge "9e and a

negative ion of charge $8e (Fig. 1747).

(a) Find the magnitude and direction of the resultant

force on the electron.

(b) Find the magnitude and direction of the electrons

instantaneous acceleration.

Answers

A)1.78*10^-16

B)1.95*10^14

Please explain how to get these answers. Points will be rewarded to clearest answer

An electron is near a positive ion of charge "9e and a negative ion of charge $8e (Fig. 17-47). Find the magnitude and direction of the resultant force on the electron. Find the magnitude and direction of the electron's instantaneous acceleration.

Explanation / Answer

The magnitude of the combined force, Fc, from the two ions using the law of cosines is:
Fc^2 = a^2 + b^2 - 2ab cos 55.6 = (1.01E-16 N)^2 + (2.05E-16 N)^2 - 2(1.01E-16 N)(2.05E-16 N) cos55.6 = 2.88E-16 N^2

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