(a) A proton is released from rest and accelerates freely through a potential di

Question

(a) A proton is released from rest and accelerates freely through a potential difference of size 215 V.
It will seek a  ---Select--- lower higher N/A - wants to maintain  potential energy
by seeking a  ---Select--- lower higher N/A - wants to maintain  voltage
so its ?V will be:  ---Select--- positive negative  N/A - it is zero

Also, what is its final speed?  m/s

(b) Repeat part a, but with an electron.
It will seek a  ---Select--- lower higher N/A - wants to maintain  potential energy
by seeking a  ---Select--- lower higher N/A - wants to maintain  voltage
so its ?V will be:  ---Select--- positive negative  N/A - it is zero

Also, what is its final speed?  m/s

(c) Which charge gained more kinetic energy?  ---Select--- proton electron N/A - they gained the same amount

Explanation / Answer

it will seek a lower PE
by seeking alower V

do delta V will be negative

dPE = q dV = 1/2 mv^2

215*1.6E-19 = 0.5*1.67E-27*v^2

v=2.03E5 m/s m/s

b) it will go to lower PE

but PE = q V

so lower PE means bigger V, so a higher V

so delta v will be positive

215 = 0.5*9.11E-31*v^2

v=8.69E6 m/s

c) same KE

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