A block of mass 5.65 kg is pushed up against a wall by a force P that makes an a

Question

A block of mass 5.65 kg is pushed up against a wall by a force P that makes an angle of theta= 50.0 degree angle with the horizontal as shown below. The coefficient of static friction between the block and the wall is 0.243. (a) Determine the possible values for the magnitude of P that allow the block to remain stationary. (If there Is no maximum, enter NONE In that answer blank.) |Pmax | = N |Pmin| = N (b) What happens if |P|, has a larger value than |Pmax|? . The block slides up the wall. The block does not slide along the wall. The block slides down the wall. What happens If |P| has a smaller value than |Pmin|? The block slides up the wall. The block does not slide along the wall. The block slides down the wall.

Explanation / Answer

For maximum value:

Psin(theta) = uPcos(theta) + mg

Solving we get

P = mg/(sin(theta) - ucos(theta))

Pmax = 3.45*9.8/(sin 50 - .251*cos50) = 55.91 N

For Pmin = 3.45*9.8/(sin50 + .251cos50) = 36.45 N

If it has largeer value it will sldie up

If it has lower value it will fall down.

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