We can model the cell membrane of an animal cell as a capacitor with a resting m

Question

We can model the cell membrane of an animal cell as a capacitor with a resting membrane potential of 67mV, a width of 7.0nm, and a dielectric constant of 80.

a.) if we measure the charge on the inner surface of the membrane to be 5x10^-11 C, then what is the capacitance of the capacitor?

b.) Calculate the magnitude of the electric field inside the membrane.

c.) How much electrical energy is stored as a result of this charge separation?

Please answer with as much detail as possible, diagrams are great!

Constants that may be needed are:

E_o = 8.85x10^-12 k= 8.99x10^-9 radius of an animal cell= 2.0x10^-5m

Explanation / Answer

a) charge = capacitance * voltage .

therefore, capcitance = charge/ voltage = 0.000746 pF

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