A man who carries a harmful sex-linked gene on his X chromosome, will pass the g
ID: 22953 • Letter: A
Question
A man who carries a harmful sex-linked gene on his X chromosome, will pass the gene on to
a. All of his daughters
b. Half of his daughters
c. All of his sons
d. Half of his sons
e. All of his children
A double-stranded DNA molecule that has 22% guanine will have
a. 28% thymine
b. 22% cytosine
c. 44% adenine
d. 26% uracil
e. Both A and B are correct
Which of the following variations could be subject to natural selection?
a. A dog with short legs due to malnutrition is able to crawl into holes better than his litter mates
b. A tree is not infested by a ground-dwelling beetle when the homeowner cuts the lower branches
c. A hyena is born with a spotted fur pattern that allows it to hide in the grass better than his litter mates
d. A pigeon learns that when its keeper comes near it will be fed
e. All of these variations may be acted on by natural selection
Explanation / Answer
C. all of his daughters. (and only his daughters) In humans, the male determines the sex of the child. He has and X and a Y chromosome in his cells and will pass one or the other onto his children. If he passes the X (the one with the harmful gene), the child will be female. If he passes the Y (the chromosome that doesn't carry the gene) instead, the child obviously won't have the gene and the child will also be male. None of his sons will have it, because they all got his Y instead of his X. All of his daughters will have it because they got his X, and unlike a woman, the man only has 1 type of X to donate. b. 22% cytosine
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