At 430°C, the equilibrium constant (Kp for the reaction 2NO(g) + 028)2NO2(8) is

Question

At 430°C, the equilibrium constant (Kp for the reaction 2NO(g) + 028)2NO2(8) is 1.5 × 105. In one experiment, the initial pressures of NO, 02, and NO2 are 7.1 x 10-3 atm, 9.9 × 10-2 atm, and 0.23 atm, respectively. Calculate QP and predict the direction that the net reaction will shift to reach equilibrium. What is Qp for the experiment? In which direction will the system proceed to reach equilibrium? The reaction is at equilibrium. The reaction will proceed to the right. The reaction will proceed to the left.

Explanation / Answer

2 NO (g)   +   O2 (g)   <-------------> 2 NO2 (g)

Qp = P2NO2 / P2NO x PO2

     = (0.23)^2 / (7.1 x 10^-3)^2 x 9.9 x 10^-2

Qp = 1.1 x 10^4

Kp = 1.5 x 10^5

here Kp > Qp . so reaction will procedd to right

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