(b)-4.33x 106 C/m2 (c) 2.94 x 10 C/m2 (d) 1.0 x 104 C/m2 e surtaee charge densit

Question

(b)-4.33x 106 C/m2 (c) 2.94 x 10 C/m2 (d) 1.0 x 104 C/m2 e surtaee charge density? 5. The equivalent capacitance of 10 F, 20 F, and 30 F capacitors in series is (a) 0.18 F (b) 60 F c)2.1 F d)5.5 F 6. The resistance of a 100m long copper wire with diameter 2.0 mm is (a) 540 ? (b) 0.54 2 (c) 1.9 ? (d) 190 ? 7. You have a 240 ? resistor and wish to combine it with a second resistor to make an equivalent resistance of 200 2. You should add (a) a 40 ? resistor in series (b) a 40 92 resistor in parallel (c) a 440 ? resistor in parallel (d) a 1200 ? resistor in parallel 8. A 9.0 V battery, 1002 resistor, and 2402 resistor are in series. The power delivered by the battery (a) 0.24W (b) 4.2 W (c) 0.026W (d) 0.09w 9. The electric field and gravitational field (a) have the same units (b) both depend on mass (c) are both attractive and repulsive forces (d) both have inverse-square distance dependence T F T F T F 1131@ 3a@ la@???? T F 130033 Lu T F 14000 34

Explanation / Answer

5,

equivalent capacitance

1/C =1/10 +1/20 +1/30

C =5.45 F =5.5 F (approx)

6.

Resistivity of copper is

p=1.68*10-8 ohms

Area of copper wire

A=pi*D2/4 =pi*(2*10-3)2/4 =3.14*10-6 m2

Resistance of copper wire

R=pL/A =(1.68*10-8)(100)/(3.14*10-6)

R=0.535 ohms =0.54 ohms

7.

Answer is D)a 1200 ohms resistor in parallel

For equivalent resistance of 200 ohms the resistors has to be arranged in parallel

1/Req =1/R1 +1/R2

1/200 =1/240 +1/R2

R2 =1/200 -1/240

R2=1200 ohms

8.

equivalent resistance

R=100+240 =340 ohms

Power developed by battery

P=V2/R =92/340 =0.2384 W

P=0.24 W

9.

ELectric field is given by

E=KQ/r2

Gravritonal Force is

F=GMm/r2

Therefore answer is

(d)both have inverse-square distance dependence

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