DATA SHEET: ONE-DIMENSIUNAL CULLISIONS mA-52.5. og / 4SzS L my - 304 3/3 . L 4.
ID: 2303869 • Letter: D
Question
DATA SHEET: ONE-DIMENSIUNAL CULLISIONS mA-52.5. og / 4SzS L my - 304 3/3 . L 4. . .04 Units Collision 1 Collision 2 Collision 3 Collision 4 Collision 5 (41) bec0.3.72 81444 Fo (352 sec 2 .17190 . ..34 Sec 0.425 - S o 01743 See 6.5.12 0-1540.43 to43 - O.S21 (43) i (A ) (v) (PA) 3) Under ideal conditions (perfectly level air track, no friction, perfectly elastic bumpers in collisions #3 - #5, etc.): D) In which of the five collisions (#1 - #5) would each glider's individual momentum be constant? b) In which of the five collisions (#1 - #5) would each glider's individual kinetic energy be constant? c) In which of the five collisions (#1 - #5) would the two gliders' total momentum be constant? d) In which of the five collisions (#1 - #5) would the two gliders' total kinetic energy be constant? (P ) 0.008 0.684 097 0.04 0.131 -0.14 2. 155 .764-3 -.9 AKIK )Explanation / Answer
3. a) In collision 5, the initial momentum of A (rounding off with one significant digit) =0.2 kgm/s and the final momentum of A (rounding off with one significant digit)=0.2 kgm/s. Similarly for B, initial momentum = 0.2 kgm/s and final momentum =0.2 kgm/s. So in collsion 5 the individual momenta of each glider is constant.
b) In collision 5, the initial KE of A (rounding off with one significant digit) =0.07 J and the final momentum of A (rounding off with one significant digit)=0.07 J. Similarly for B, initial KE = 0.04 J and final KE =0.04 J. So in collsion 5 the individual KE of each glider is constant.
c) Again in collision 5, the total initial momentum of the system is 0.2 kgm/s (rounding off to one significant digit) and total final momentum of the system is 0.2 kgm/s (after rounding off to one significant digit). Similarly in collision 3, the total initial momentum of the system is 0.18 kgm/s (rounding off to two significant digits) and total final momentum of the system is 0.18 kgm/s (after rounding off to two significant digits). So in collisions 3 and 5 the total momentum of the system is constant.
d) In collision 4, the total kinetic energy initially is 0.074 J and the final kinetic energy is 0.074 J. Also in collision 5, the total kinetic energy initially is 0.1 J (rounding off to one significant digit) and the total kinetic energy finally is 0.1 J (rounding off to one significant digit). So in collisions 4 and 5 the total kinetic energy is constant.
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