Chapter 22, Problem 017 Your answer is partially correct. Try again. Two charged
ID: 2304521 • Letter: C
Question
Chapter 22, Problem 017 Your answer is partially correct. Try again. Two charged beads are on the plastic ring in Figure (a). Bead 2, which is not shown, is fixed in place on the ring, which has radius R62.4 cm. Bead 1 is initially on the x axis at angle ? 0°. It is then moved to the opposite side, at angle ?-180°, through the first and second quadrants of the xy coordinate system. Figure (b) gives the x component of the net electric field produced at the origin by the two beads as a function of ? and Figure belo gves they component. The vertical axis scales are set y , 15 LO. and Eys =-9.27 x 104 N/C (a) At what positive angle ? is bead 2 located? (Note: bead 2 is negative charged). What are the charges of (b) bead 1 and (c) bead 2? Ring Bead 1 90° 180° 0 180°Explanation / Answer
given there are two charged beads
bead 1 is initially at theta = 0 deg, and is moved to 180 deg through 1st and 2nd quadrants
let bead 2 be at angle phi wrt the +x axis
now, from plot b
the x component of electric field is given
when theta = 0 deg, Ex = -Exs = -5.15*10^4 N/C
when theta = 180 deg, Ex = Exs = 5.15*10^4 N/C
for y component
when theta = 0 deg, Ey = 0
when theta = 180 deg, Ey = 0
when theta = 90 deg, Ey = -Eys = -9.27*10^4 N/C
hence
Ex is 0 when bead 1 is on y axis, hence bead 2 is on y axis too
hence
a. phi = 270 deg
b. let charge on bead 1 = q1
charge on bead 2 = q2
Ey = 0 for theta = 0
hence
q2 = 0
also,
Ex = -Exs for theta = 0 deg
hence
5.15*10^4 = k*q1/0.624^2
q1 = 2.233*10^-6 C = 2.23 uC
hence
q1 = 2.23 uC
q2 = 0 C
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.