me: Class: Date: _ ID: A est 3 2018 ltiple Choice enti?y the choice that best co

Question

me: Class: Date: _ ID: A est 3 2018 ltiple Choice enti?y the choice that best completes the statement or answers the question 1. How much energy is in a 30 kHz photon of AM-radiation? a. 1.5 x 10-38 J b. 8.6 x 10-30 J c. 4.1x 10-29 J d. 3.3x 10-30 J e. 2.0x 10-29 J 2. The threshold wavelength for photoelectric emission of a particular substance is 400 nm. What is the work function (in eV)? a. 3.1 b. 2.0x 10-14 C. 4.0 x 10-10 d. 3.1 x 10-19 e. 2.5 photon whose energy is 60 keV is scattered off an electron at a 90 ° angle. What is the wavelength of the scattered wave? a. 2.83 x 10-2 nm b. 2.20 x 10-2 nm c. 1.50 x 10-2 nm d. 2.38 x 10-3 nm e. 2.31 x 10-2 nm 3. A 4. A neutron has a mass of 1.67 × 10-27 kg. The de Broglie wavelength is 1.4 x 10-10 m, How fast is the neutron going? (in m/s) a. 3.4 x 103 b. 2.8 x 103 c. 3.9 x 103 d. 2.6 x 103 e. 1.7 x 103 An electron has been accelerated by a potential difference of 50 V. If its position is known to have an uncertainty of 0.1 nm, what is the percent uncertainty (Aplp x 100) of the electron? a. 1% b. 2% c. 10% d. >>1096 e. 5% 5.

Explanation / Answer

1. E = h f

E = (6.626 x 10^-34)(30 x 10^3)

E = 2 x 10^-29 J  

Ans(e)

2. work function = h c / threshold wavelength

= (1240 eV-nm) / 400 nm

= 3.1 eV  

Ans(a)

3. (lambda)f - (lambda)i = ( h / m0 c)(1 - cos(theta))

  
lambda - (1240 eV-nm / (60 x 10^3 eV)) = (6.626 x 10^-34 / (9.109 x 10^-31 x 3 x 10^8))(1 - cos90)

lambda = (2.07 x 10^-11 ) + (2.4247 x 10^-12)

lambda = 2.31 x 10^-11 m OR 2.31 x 10^-2 nm

Ans(e)

4. p = h / wavelength = (6.626 x 10^-34)/(1.4 x 10^-10)

(1.67x 10^-27) v = 4.733 x 10^-24

v = 2834 m/s OR 2.8 x 10^3 m/s

Ans(b)

  

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