Compute the energies (in J) of a photon of light produced by: a solid state Nd:Y

Question

Compute the energies (in J) of a photon of light produced by: a solid state Nd:YAG laser with wavelength 1064 nm; an argon ion laser with wavelength 488 nm, and an excimer Xe-Cl laser with wavelength 308 nm. Which laser produces the most energetic photon? What type of electromagnetic radiation does each of these wavelengths correspond to? If the answer is visible light, what is its color? Which of these lasers produce photons of light with energy sufficient to break a chemical bond of energy 6 10^-19 J?

Explanation / Answer

(A) Photon energy E = hc/

h = plank constant = 6.626 x 10-34 m2 kg / s

c = speed of light = 3 x 108 m/s

1 =wavelength1 = 1064 x 10-9 m

2 =wavelength2 = 488 x 10-9 m

3 =wavelength3 = 308 x 10-9 m

E1 = (6.626 x 10-34 x 3 x 108)/1064 x 10-9 = 1.868 x 10-19Joule

E2 = (6.626 x 10-34 x 3 x 108)/488 x 10-9 = 4.073 x 10-19Joule

E3 = (6.626 x 10-34 x 3 x 108)/308 x 10-9 = 6.454 x 10-19 Joule

So excimer Xe-Cl laser produce photons with highest energy

(B)

Wavelength in visible spectrum is 390 - 700 nm.

1 =1064 nm, is near infrared region, outside Visible range.

2 =488 nm, is in visible light region, with blue color [Blue color range: 450–495 nm]

2 =308 nm, is near ultraviolet region, outside Visible range.

(C)

So clearly 3 =308 nm has the more energy than 6x10-19 J and will able to break chemical bond.

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.