A 2.0 kg pendulum bob swings back and forth. At the very bottom of the swing, th

Question

A 2.0 kg pendulum bob swings back and forth. At the very bottom of the swing, the height of the pendulum bob is 0.0 m and the velocity of the pendulum bob is 2.1 m/s. (Neglect Friction)

What is the kinetic energy of the pendulum bob at the bottom of the swing?

and

A 2.0 kg pendulum bob swings back and forth. At the very bottom of the swing, the height of the pendulum bob is 0.0 m and the velocity of the pendulum bob is 2.1 m/s. (Neglect Friction)

What is the kinetic energy of the pendulum bob at the bottom of the swing?

and

A 2.00 kg pendulum bob swings back and forth. At the very bottom of the swing, the height of the pendulum bob is 0.000 m and the velocity of the pendulum bob is 2.10 m/s. (Neglect Friction)

What is the maximum height of the pendulum bob during the swing?

Three part question, thanks in advance! :)

Explanation / Answer

Seems part 1 and part 2 are same.

Kinetic energy = (1/2) m V^2

So m = 2 kg, V =2.1m/s

At that instant i.e. at te bottom Kinetic energy = 0.5 * 2 * 4.41 = 4.41 J

By law of energy conservation. Sum of potential energy + kinetic energy is constant.

So P.E at the bottom is mgh = 0 since h =0

So Total energy at bottom = 4.41J

WHen Max height is reached Pendulams velocity will be 0. SO k.E is zero.

So Max height H is when mgH = 4.41J

So H = 4.41/( 2*9.8) = 0.225m

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