A 2-way set associative cache holds 8 16-word blocks. What is the correct breakd

Question

A 2-way set associative cache holds 8 16-word blocks. What is the correct breakdown of the bits in a 32 bit address?

a. 2 bits for the byte displacement

4 bits for the block displacement

2 bits for the cache index

24 bits for the tag

b. 2 bits for the byte displacement

2 bits for the block displacement

0 bits for the cache index

28 bits for the tag

c. 2 bits for the byte displacement

2 bits for the block displacement

4 bits for the cache index

24 bits for the tag

d. 2 bits for the byte displacement

3 bits for the block displacement

4 bits for the cache index

23 bits for the tag

a. 2 bits for the byte displacement

4 bits for the block displacement

2 bits for the cache index

24 bits for the tag

b. 2 bits for the byte displacement

2 bits for the block displacement

0 bits for the cache index

28 bits for the tag

c. 2 bits for the byte displacement

2 bits for the block displacement

4 bits for the cache index

24 bits for the tag

d. 2 bits for the byte displacement

3 bits for the block displacement

4 bits for the cache index

23 bits for the tag

Explanation / Answer

Answer:)

d

16*4*8=24*22*23=29

32-9=23

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