The probability of having a given phenotype is 9/16 free earlobes, dark hair 3/1

Question

The probability of having a given phenotype is 9/16 free earlobes, dark hair 3/16 free earlobes, light hair 3/16 attached earlobes, dark hair 1/16 attached earlobes, light hair Additional Double-Factor Inheritance Problems (Two Traits Followed from One Generation to the Next) In horses, black color (B) dominates chestnut color (b). Trotting gait (T) dominates pacing gait (). A cross is between a horse homozygous for both black color and pacing gait and a horse homozygous for both chestnut color and trotting gait. List the probable genotype and phenotype of offspring resulting from such a cross. Genotype ; phenotype

Explanation / Answer

Ans 5 : Genotype - BbTt, Phenotype - Black color, Trotting gait.

One of the parents is BBtt and the other is bbTT. So, there is a cross between the genotypes Bt and bT, which will result in BbTt offspring.

Bt X bT ==> BbTt (Black color, Trotting gait).

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.