The probability of obtaining no defective components from a sample of 50 items i

Question

The probability of obtaining no defective components from a sample of 50 items is 0.34. while the probability of obtaining one defective component is 0.46. What is the probability of (a) obtaining not more than one defective component in the sample and (b) obtaining more than one defective component in the sample?

1) The probability of obtaining no defective components from a sample of 50 items is0.34. while the probability o obtaining ane defective component is 0.46. Wha is the probability af () obtaining not more than one defective component in the sample and (b) obtaining more than one defective component in the sample?

Explanation / Answer

P( no defective component ) = 0.34

P( One defective component ) = 0.46

P( More than one defective component) = 1 - P( One or less defective component ) = 1 - [ P( No defective component ) + P( One defective component ) ] = 1 - [ 0.46 + 0.34 ] = 1 - 0.8 = 0.2

So, P( Not more than one defective component ) = P( One defective component ) + P( no defective component ) = 0.46 + 0.34 = 0.80

P( More than one defective component ) = 0.2 .

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.