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Answer are suppose to be Calcium chloride. b) 1) LB+ plate - both tranformed and

ID: 254745 • Letter: A

Question

Answer are suppose to be

Calcium chloride.

b) 1) LB+ plate - both tranformed and untransformed grow, because there are no antibiotics.

2) The tranformed E.coli would grow. Ampicilin resistance comes from plasmid.

3)Both tranformed and untransformed grow. The resistance for nalidixic acid comes from the chromosomal DNA.

4)LB - no growth.

5)LB amp- growth of both tranformed and untransformed

6) growth of both tranformed and untransformed.

I just want to a second opinion, and any explantion would be appriciated.

You just completed a transformation plasmid. LMN2 is a strain of E. coli that has been made competent by the inclusion of a salt in an artificial competency protocol Name the salt used: LMN2 is naturally resistant to Nalidixic Acid due to chromosomal Naladixic AcidR. Cell: Plasmid: pTer contains the following OR? pTer GF Ampicillin Describe the expected growth on each of the six plates below. Describe what you would see and if there is growth, indicate why the growth was able to occur on the plate (specify where the resistance is coming from-chromosomal or plasmid) LB + LB Amp+ LB Naladixic Acid + LB- LB Amp- LB Naladixic Acid -

Explanation / Answer

The options and explanations you provided are absolutely correct.

Calcium chloride. It is used as salt in transformation procedure, it increases the ability of prokaryotic cell to incorporate plasmid DNA.

b) 1) LB+ plate - both tranformed and untransformed grow, because there are no antibiotics, and presenece of nutrient growth medium.

2) The tranformed E.coli would grow. Transformed cell has ampicilin resistance gene, and it comes from plasmid.

3) Both tranformed and untransformed grow. The resistance for nalidixic acid comes from the chromosomal DNA.

4) LB - no growth. Because there is no nutrient growth medium for the growth of bacteria.

5) LB amp- growth of both tranformed and untransformed. Without ampicilin (amp-) both cells will grow.

6) Growth of both tranformed and untransformed. Without nalidixic acid, both cells will grow.

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