1) You have isolated ten new mutants that have eye defects; assume that each mut

Question

1) You have isolated ten new mutants that have eye defects; assume that each mutant only has one mutation and all mutations are recessive. To place them into comple make mate each combination of animals. A "+ indicates a wild-type phenotype in the FI progeny. A"-" indicates a mutant eye phenotype in the Fl progeny mentation groups, you 1 2 3 4 5 6 789 10 10 a) How many complementation groups were identified among the new mutants? What are the complementation groups? b) How should the two unknowns in the table be scored (+or -)? c) Mutant 6 has a mutation in gene A, which encodes an enzyme. The genomic organization of gene A is indicated below; exons 2 and 3 encode the active domain of the enzyme i.e., the critical part of the enzyme). On this diagram, indicate where POINT mutations (defined as a single nucleotide insertion/deletion/substitution) that give these phenotypes would be located. Give the BEST possible answer for each. ATG STOP i) Makes large amounts of transcript A. i) Makes an unstable transcript A. ii) Makes a completely different protein product. iv) Makes a protein that is not very active.

Explanation / Answer

- And – is no complementation. On the same gene. + and – is complementation. On the different gene. - +- and +-+ is complementation. -+- and -+- is no complementation. There are atleast three complementation groups. There are atleast three genes. Q1 refers about + and Q2 refers about +. 1,5 comes under one group 2,3,4,6,7 comes under another group. 1, 5 is another group 8 is in another group and 9 might be its allele and 10 is different and do not complement to other 8,9,10 are mutants of group 2,3,4,6,7 Due to a point mutation in group 6, results in formation of a completely new product.

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