1) You have isolated ten new mutants that have eye defects; assume that each mut

Question

1) You have isolated ten new mutants that have eye defects; assume that each mutant only has one mutation and all mutations are recessive. To place them into complementation groups, you make mate each combination of animals. A"+" indicates a wild-type phenotype in the F1 progeny. A"-" indicates a mutant eye phenotype in the F1 progeny 1 234 5 67 8910 4 10 a) How many complementation groups were identified among the new mutants? What are the complementation groups? b) How should the two unknowns in the table be scored (+ or -)? c) Mutant 6 has a mutation in gene A, which encodes an enzyme. The genomic organization of gene A is indicated below; exons 2 and 3 encode the active domain of the enzyme (i.e., the critical part of the enzyme). On this diagram, indicate where POINT mutations (defined as a single nucleotide insertion/deletion/substitution) that give these phenotypes would be located Give the BEST possible answer for each. ATG i Makes large amounts of transcript A. ii) Makes an unstable transcript A. iii) Makes a completely different protein product. iv) Makes a protein that is not very active

Explanation / Answer

- And – is no complementation. On the same gene. + and – is complementation. On the different gene. - +- and +-+ is complementation. -+- and -+- is no complementation. There are atleast three complementation groups. There are atleast three genes. Q1 refers about + and Q2 refers about +. 1,5 comes under one group 2,3,4,6,7 comes under another group. 1, 5 is another group 8 is in another group and 9 might be its allele and 10 is different and do not complement to other 8,9,10 are mutants of group 2,3,4,6,7 Due to a point mutation in group 6, results in formation of a completely new product.

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