Find the emitted power per square meter of peak intensity for a 3000 K object th

Question

Find the emitted power per square meter of peak intensity for a 3000 K object that emits thermal radiation Express your answer to three significant figures and include the appropriate units P= Value Units Submit Previous Answers Request Answer Incorrect. Try Again: 3 attempts remaining Part B Find the wavelength of peak intensity for a 3000 K object that emits thermal radiation Express your answer to three significant figures and include the appropriate units peak = 1 Value Units Submit iou X Incorrect; Try Again: 4 attempts remaining Part C Find the emitted power per square meter of peak intensity for a 50,000 K object that emits thermal radiation Express your answer to three significant figures and include the appropriate units P= Value Units

Explanation / Answer

First we need to remember:

1) Stefan Boltzmann eqn

E= sigma× T^4

sigma = 5.67 × 10^(-8) W/m^2

2) Wein displacement law

Lambda(max) = b/T

b= 2.8978 × 10^(-3) mK

Ans A) P = 5.67×10^(-8) × 3000^4

=4592700 W/m^2

= 4.59 MW/m^2

Ans B) wavelength = 2.89777/ 3000

= 0.9659 mm

= 966 micometers

Ans C) Power = 5.67×10^(-8)×50000^(4)

= 354375000 kW/m^2

= 354 GW/m^2

Ans D) wavelength = 2.89777/50000

= 57.9 micometers.

We were glad to answere this question. Let us know if you have any further queries. Do like the answere if you were satisfied.

Regards.

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.