do question 16 13. A stone is thrown upward from ground level. The initial speed
ID: 2895778 • Letter: D
Question
do question 16
Explanation / Answer
S(t) = So + Vot - At²/2
S(t) = 90 = So - 4t - 16.1t² …………………………….( 1 )
S(t+2) = 10 = So - 4(t+2) - 16.1(t+2)²
10 = So - 4t - 8 - 16.1(t² + 4t + 4)
10 = So - 4t - 8 - 16.1t² - 64.4t - 64.4
10 + 8 + 64.4 = So - 68.4t - 16.1t²
82.4 = So – 68.4t - 16.1t² ………………………………( 2 )
solve equation ( 1 ) & ( 2 )
So - 4t - 16.1t² = 90
So – 68.4t - 16.1t² = 82.4
64.4t = 7.6
t = 7.6/64.4 = .11801
90 = So - 4(.11801) - 16.1(.11801)²
So = 90.6962 ft.
The stone was thrown from a height of 90.6962 ft
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