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Describe three different ways to solve x^2 - 2x - 15 = 0. Which method do you pr

ID: 2895922 • Letter: D

Question

Describe three different ways to solve x^2 - 2x - 15 = 0. Which method do you prefer and why? OPEN ENDED Write a quadratic equation with no real solutions. FIND THE ERROR Lakeisha and Juanita are determining the number of solutions of 5y^2 - 3y = 2. Lakeisha5y^2 - 3y = 2 b^2 - 4ac = (-3)^2 - 4(5)(2) = - 31 Since the discriminant is negative, there are no area solutions. Juanita 5y^2 - 3y = 2 5y^2 - 3y - 2 = 0 b^2 - 4ac = (-3)^2 - 4(5)(-2) = 49 Since the discriminent if positive, there ore two reol roots. Who is correct? Explain your reasoning.

Explanation / Answer

Answer : Lakeisha is incorrect because first we need to write the equation in standard form y = ax^2+bx+c

And then we have to find Discriminant. Juanita has performed the answer correctly.

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