After opening the parachute, the descent of a parachutist follows a linear model
ID: 2900877 • Letter: A
Question
After opening the parachute, the descent of a parachutist follows a linear model. At 7:28 P.M., the height of the parachutist is 6150 feet. At 7:31 P.M., the height is 3450 feet. Use a linear equation that gives the height of the parachutist in terms of the time to find the time when the parachutist will reach the ground. After opening the parachute, the descent of a parachutist follows a linear model. At 7:28 P.M., the height of the parachutist is 6150 feet. At 7:31 P.M., the height is 3450 feet. Use a linear equation that gives the height of the parachutist in terms of the time to find the time when the parachutist will reach the ground. After opening the parachute, the descent of a parachutist follows a linear model. At 7:28 P.M., the height of the parachutist is 6150 feet. At 7:31 P.M., the height is 3450 feet. Use a linear equation that gives the height of the parachutist in terms of the time to find the time when the parachutist will reach the ground.Explanation / Answer
since it is a linear relation
h=u*t
6150=u*(t)
3450=u*(t+3) (since, 7:31 pm-7:28 pm=3 mins diffrence)
for heaight =0
0=u*(t+x)
solving we gwt u=-900
and thus x= 41/6=6.83 mins
so time for heaight becoming zero = 7:28+6.83=7:35:23
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