A multinomial experiment with k=3 cells and n=440 produced the data shown below.
ID: 2906498 • Letter: A
Question
A multinomial experiment with k=3 cells and n=440 produced the data shown below. Cell 1 Cell 2 Cell 3 ni 115 114 211 If the null hypothesis is H0:p1=.25, p2=.25, p3=.5 and using ?=0.05, then do the following:
(a) Find the expected value of Cell 1. E(Cell 1) = 110
(b) Find the expected value of Cell 2. E(Cell 2) = 110
(c) Find the expected value of Cell 3. E(Cell 3) = 220
(d) Find the test statistic. ?2= .741
(e) Find thep-value.
The final conclusion is
A. We can reject the null hypothesis that p1=.25, p2=.25, p3=.5 and accept that at least one of the multinomial probabilities does not equal its hypothesized value.
B. There is not sufficient evidence to reject the null hypothesis that p1=.25, p2=.25, p3=.5.
Explanation / Answer
Ans:
Test statistic:
Chi square score=0.741
df=3-1=2
p-value=CHIDIST(0.741,2)=0.6904
There is not sufficient evidence to reject the null hypothesis that p1=.25, p2=.25, p3=.5.
Option B is correct.
Expected Observed (O-E)^2/E 1 115 110 0.227 2 114 110 0.145 3 211 220 0.368 Total= 440 440 0.741Related Questions
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