TI-84Stdent senaie (20) ?wd bit mu (free)--(E4.11) (A) p.2 Greg Maddux throws 30
ID: 2907786 • Letter: T
Question
TI-84Stdent senaie (20) ?wd bit mu (free)--(E4.11) (A) p.2 Greg Maddux throws 300 pitches, of right in his boast that over 75% of his pitches (in general, are strik which 237 are strikes. Toa 1% level of significance, is be A cannon is fired 10 times; the mean distance traveled by the projectile is 2.2 km, with a standard deviation of .3 km. To a 5%, level of significance, can it be asserted that the standard deviation of the distances traveled by the projectile (in general) is over .25 km? Assume that the distances of all the cannon shots are normally distributed. 6Explanation / Answer
Solution:-
5)
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: P < 0.75
Alternative hypothesis: P > 0.75
Note that these hypotheses constitute a one-tailed test.
Formulate an analysis plan. For this analysis, the significance level is 0.01. The test method, shown in the next section, is a one-sample z-test.
Analyze sample data. Using sample data, we calculate the standard deviation (S.D) and compute the z-score test statistic (z).
S.D = sqrt[ P * ( 1 - P ) / n ]
S.D = 0.025
z = (p - P) / S.D
z = 1.60
where P is the hypothesized value of population proportion in the null hypothesis, p is the sample proportion, and n is the sample size.
Since we have a one-tailed test, the P-value is the probability that the z-score is greater than 1.60.
Thus, the P-value = 0.055
Interpret results. Since the P-value (0.055) is greater than the significance level (0.01), we have to reject the null hypothesis.
From the above test we do not have sufficient evidence in the favor of the claim that he is right in over 75% of this pitches are strikes.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.