l T-Mobile LTE 9:02 AM 89% Problem 5 Problem 5.pdf Group Problem 5 The illustrat
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l T-Mobile LTE 9:02 AM 89% Problem 5 Problem 5.pdf Group Problem 5 The illustratioe shows the graph of a polynoemial function (a) Is the degree of the polynomial even or odd? (b) Is the leading coefficient positive or negative? (c) Is the function even, odd, or neither (d) Why is (3necessarily a factor of the polynomial (c) What is the minimum degree of the polynomial? n Make up three diffcrent polynomials whose graphs could look like the on shown Compare yours to those of other group members, What similaritics do you see? What differences? CoursesCalendar To Do Notifications InboxExplanation / Answer
Ans: a) As the graph has 4 zeroes it's an equation of degree 4 hence of even degree.
b) As the polynomial opens upwards its leading coefficient is positive.
c) The function is neither even nor odd as the graph isn't symmetrical about either x or y axis.
d) At x = -3 we have a zero of degree 2 as we can see fron the graph that the sign of function doesn't change on either side of x = -3. So (x+3)^2 will be a factor of the function.
e) Minimum degree is 4. As the graph cuts the x axis at 3 points out of which -3 is a zero of degree 2.
f) We can see that the polynomial is of form a (x+3)^2(x-1)(x-4)
Where a> 0 hence a can take different values giving us different polynomials.
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