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l T-Mobile LTE 9:20 PM flipitphysics.com FlipltPhysicsCopy of Electricity & Magnetism | University Physies (calculus-bas 48% Homework: Gauss' Law Spheres Welcome to this IE. You may navigate to any page you've seen already using the IE tab on the right. Spherical Shell Insulator Point Charge and Charged +0 Line Charge and Cha Line Charge and Chr Conducting Siab An insulator in the shape of a spherical shell is shown in cross-section above. The insulator is defined by an inner radius a-4 cm and an outer radius b-6 cm and carries a total charge of Q·+9 K (1 10 C). (You may assume that the charge is distributed uniformly throughout the volume of the insulator), What is Ey the y-component of the electric field at point P which is located at (x,y) (0, -5 cm) as shown in the diagram Tech SuppantExplanation / Answer
We know from Gauss Law
phi = integral E.dA = Q(enclosed)/e0
E(4 pi r^2) = Q(enclosed)/e0
Q(enclosed) = 4/3 pi (r^3 - a^3)
Q(enclosed) = Q(r^3 - a^3)/(b^3 - a^3)
E = 1/4 pi e0 Q(r^3 - a^3)/(b^3 - a^3)
E = 9 x 10^9 x 9 x 10^-6 [(5^3 - 4^3) x 10^-6/(6^3 - 4^3) x ] = 3.25 x 10^4 N/C
Hence, E = 3.25 x 10^4 N/C
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