Use Table (Standard Normal Distribution) to find the proportion of observations
ID: 2919548 • Letter: U
Question
Use Table (Standard Normal Distribution) to find the proportion of observations that satisfies each of the following statements. In each case, shade the area under the curve that is the answer to the question. 14. 21. 23. 20. -3 2 101 23 3 -2 -1 0 1 23 3 -2-10 12 3 z is less than -1.83 z is greater than 2.18 z is between 1.42 and 2.68 15. Find the percentile for the indicated z-score. z -2.0 b. c. d. z1.12 1.12 16. Find the value of z from the standard normal distribution that satisfies each of the following conditions. (Use the value of z from Table that comes closest to satisfy ing the condition.) Area is 0.2981 17. Find the z-score of 125.18, given a distribution with a mean of 101 and standard deviation of 62. 18. Given a distribution with a mean of 117 and standard deviation of 42, find a value with a z-score of -0.94Explanation / Answer
17
we know that the formula for the z score is given as
Z = (x-mu)/sd
here x = 125.18 , mu = 101 and sd = 62
putting the values we get
z = (125.18 - 101)/62 = 0.39
18
mean = 117
sd = 42
z = -0.94
again puttin the values in the equation we get x as
X = z*sd +mu
= -0.94*42 +117 = 77.52
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