How much money does the average professional football fan spend on food at a sin

Question

How much money does the average professional football fan spend on food at a single football game? That question was posed to 10 randomly selected football fans. The sample results provided a sample mean and standard deviation of $11.00 and $3.20, respectively. Use this information to construct a 99% confidence interval for the mean.

A. 11 ± 2.821( 3.20/StartRoot 10 EndRoot10 )

B. 11 ± 3.106( 3.20/StartRoot 10 EndRoot10 )

C. 11 ± 3.25( 3.20/StartRoot 10 EndRoot10 )

D. 11 ± 3.169( 3.20/StartRoot 10 EndRoot10 )

Explanation / Answer

Sample mean = 11

Std dev = 3.20

n = 10

t for 99% confidence at df = n-1 = 9 is 3.250

So, The Confidence interval is at = Sample mean +/- t*stdev/sqrt(n)

= 11 +/- 3.25*3.2/sqrt(10)

So, answer is C

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